Difficult version of boatman problem

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The discussion centers on a complex variation of the boatman problem, where a boatman must cross a river while accounting for a current. The key challenge is to calculate the time taken to reach point A, given the boat's velocity relative to the water and the river's flow rate. Participants explore mathematical expressions involving the boat's velocity and the river's current, utilizing trigonometric relationships to derive solutions. References to previous problems and solutions are made, indicating that this problem shares similarities with earlier challenges. The conversation highlights the difficulty of the problem and the collaborative effort to reach a solution.
Estudiante Curioso
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1. Problem
A boatman crosses a river of width ##D## from a point ##O##, looking to get to point ##A## on the opposite riverbank. Suppose that the flowrate is uniform with velocity of magnitude ##v_0##. The boat has a velocity ##\vec{v_1}## relative to the water, with constant magnitude, and it always points towards the point ##A##. Calculate the time that the boatman takes to ge t to point ##A##.

dWI5rhr.png


We were also hinted that it may be useful to state that ##\vec{r_A}-\vec{r_B}=\alpha(t)\vec{v_1}## (because ##\vec{v_1}## points to ##A##), and then derive that expression.

2.The attempt at a solution
First I noticed that since ##||\vec{v_1}||## is constant, its derivative must be perpendicular to it. So the plan was to project ##\vec{v_b}## (obtained from the previous derivative) over the unitary vectors ##\hat{\vec{v_1}}## and ##\hat{\dot{\vec{v_1}}}## and then I would get two expressions from the previous derivative, from where I could potentially obtain ##\alpha(t)## through integration or a differential equation. I also noted that those unitary vectors define polar coordinates with respect to ##A##.

I arrived to the expressions $$v_1+\vec{v_0} \hat{v_1} = \alpha'(t) v_1$$ and $$v_0 \hat{\dot{\vec{v_1}}}= \alpha(t) ||\dot{\vec{v_1}}||$$
where I could use trigonometry to replace the dot products on the left with ##sin(\theta)## and ##cos(\theta)## (where ##\theta## is the angle between ##\vec{v_0}## and ##\vec{v_1}##), but I am completely puzzled as what to do with ##||\dot{\vec{v_1}}||## and if this method actually works.
 

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I do believe this problem has the same mathematical solution as one in which point ## A ## moves with a constant velocity upward, and the water has no flow of current. This same problem was given by @micromass in problem 4 of his October 2016 challenge. https://www.physicsforums.com/threads/micromass-big-october-challenge.887447/ Note: You subtract ## y=v_o t ## from the y coordinate of the solution of the challenge problem. The problem gets solved, (I solved it), around posts 61-68 of the discussion. @Chestermiller also supplied portions of the solution.## \\ ## Hopefully, I'm not breaking the Physics Forums rules by supplying the solution. This is really a non-trivial problem, and in general, neither the student or the homework helper would be expected to solve this problem routinely.
 
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Thank you for your reply. I'm looking at the solution of the problem you posted, but I'm having a hard time understanding it. I'll keep trying.
Edit: I hadn't seen posts after 60, now it's much more clear.
 
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