Diffraction grating and wavelength

  • Thread starter CAH
  • Start date
  • #1
CAH
48
0
Hi I've attached the question and mark scheme,

I don't understand part 6(d)... Why have they used sin90?

nλ=dsinθ

If there is another order beam how can it be known the angel at which it exists from the zero order?
Thanks
 

Attachments

  • image.jpg
    image.jpg
    37.9 KB · Views: 418
  • image.jpg
    image.jpg
    23.5 KB · Views: 377
  • image.jpg
    image.jpg
    24.5 KB · Views: 418

Answers and Replies

  • #2
35,497
11,936
Why have they used sin90?
That is the largest angle where you can observe anything and it maximizes the sine. Either something is observable at this or a smaller angle, or it is not observable at all.
If there is another order beam how can it be known the angel at which it exists from the zero order?
The 0th order is always at 0 degrees.
 

Related Threads on Diffraction grating and wavelength

  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
803
Replies
10
Views
10K
  • Last Post
Replies
11
Views
3K
  • Last Post
Replies
3
Views
2K
Replies
1
Views
3K
Replies
6
Views
4K
Replies
9
Views
11K
  • Last Post
Replies
1
Views
1K
Top