Diffraction Grating: Laser Illumination & 643 nm Wavelength

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Homework Help Overview

The discussion revolves around a problem involving a diffraction grating illuminated by a laser, specifically focusing on calculating the distances to the first and second maxima for a given wavelength. The problem is situated within the context of wave optics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to solve for the distances to the maxima using a specific equation related to diffraction. Questions arise regarding the correctness of the initial attempts and whether alternative methods exist.

Discussion Status

Some participants have shared their calculated results, but there appears to be confusion regarding the application of the equation and the values used. The discussion is ongoing with requests for clarification on the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the resources they can reference. There is also a focus on ensuring the accuracy of the calculations based on the provided parameters.

cyclonefb3
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Homework Statement



A laser is used to illuminate a diffraction grating that has spacing of 637 lines per mm. The grating sits 11.6 cm in front of a screen. Find the distance to the first and second maxima (y1 and y2) for the laser wavelength of 643 nm. Express your answers in mm.

Homework Equations



wavelength = (s/m)(ym/sqrt(L2+ym2))

The Attempt at a Solution



s = 1/637 = .00156 mm
L = 116 mm
wavelength = 643 X 10-6 mm

I tried solving this equation for ym, but the answer I got was wrong. Is there another way to do this problem?
 
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Hi cyclonefb3,

What answers did you get?
 
I got 116 mm for both.
 
cyclonefb3 said:
I got 116 mm for both.

Can you show the details of how you got those two answers (what numbers you used and so forth)? I'm not getting that from your equation.
 

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