Max Speed Electron Ejected from Chromium Metal by Light of 250 nm Wavelength

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SUMMARY

The maximum speed of an electron ejected from chromium metal by light of 250 nm wavelength is calculated to be 4 x 105 m/s. The work function of chromium is 7.2 x 10-19 J, and the relevant equations include the kinetic energy equation KE = h vlight - Φ and the relationship between kinetic energy and speed, KE = (me ue2)/2. The mass of the electron is 9.1 x 10-31 kg, and Planck's constant (h) is utilized in the calculations.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with Planck's constant (h)
  • Knowledge of kinetic energy equations
  • Basic concepts of electron mass (me)
NEXT STEPS
  • Study the photoelectric effect in detail
  • Learn about Planck's constant and its applications in quantum mechanics
  • Explore the derivation of kinetic energy equations
  • Investigate the properties of chromium and its work function
USEFUL FOR

Students in physics, particularly those studying quantum mechanics and the photoelectric effect, as well as educators seeking to explain electron behavior in metals under light exposure.

Cursed
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Homework Statement



The work function of chromium metal is 7.2 x 10-19 J. What is the maximum speed an electron can be moving if it is ejected from chromium metal by light of wavelength 250 nm? (Answer: u= 4 x105 m/s)

Homework Equations



\Phi = h v_{0}

KE = h v_{light} - \Phi = \frac{m_{e} u^{2}_{e}}{2}

\Delta E_{light}= \Phi + KE


h is Planck's constant
v_{0} is the characteristic frequency
m_e is the mass of an electron (9.1 x 10-31 kg)
u_e is the speed of the electron


The Attempt at a Solution



7.2\times10^{-19} J = \frac{(9.1\times10^{-31} kg) (u^{2}_{e})}{2}

u_e \approx 1.3 \times 10^6 m/s
 
Last edited:
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Cursed said:

Homework Statement



The work function of chromium metal is 7.2 x 10-19 J. What is the maximum speed an electron can be moving if it is ejected from chromium metal by light of wavelength 250 nm? (Answer: u= 4 x105 m/s)

Homework Equations



\Phi = h v_{0}

KE = h v_{light} - \Phi = \frac{m_{e} u^{2}_{e}}{2}
Keep this equation in mind.

\Delta E_{light}= \Phi + KE


h is Planck's constant
v_{0} is the characteristic frequency
m_e is the mass of an electron (9.1 x 10-31 kg)
u_e is the speed of the electron


The Attempt at a Solution



7.2\times10^{-19} J = \frac{(9.1\times10^{-31} kg) (u^{2}_{e})}{2}

u_e \approx 1.3 \times 10^6 m/s
You have left out the energy of the photon, the hvlight in your earlier equation.
 

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