- #1

- 66

- 0

For part b...what wavlength do i use to find the angles for the first and second oreder maxima?...:S

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- Thread starter rojasharma
- Start date

- #1

- 66

- 0

For part b...what wavlength do i use to find the angles for the first and second oreder maxima?...:S

- #2

- 66

- 0

can anyone help me ...please..

- #3

- 83

- 1

They have different angles in both the first and second maxima.

c)

(10^-2/6000)sintheta =n(520*10^-9)

sintheta cannot exceed one

so calculate the n your own

you should calculate and do homework yourself.

I am to guide you, not to help u finish your homework

- #4

- 66

- 0

So for part b) i am supposed to find the first and sec order maxima for both wavelengths?...i see now that's why i got it wrong in first place.

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