Diffusion, isn't this the formula I'm supposed to be using?

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    Diffusion Formula
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Discussion Overview

The discussion revolves around the application of Graham's law of effusion to determine the molar mass of an unknown gas based on its diffusion time compared to nitrogen gas (N2). Participants explore the correct usage of the formula and the implications of gas properties on diffusion rates.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a scenario involving the diffusion times of an unknown gas and N2, suggesting the use of Graham's law to find the molar mass of the unknown gas.
  • Another participant questions which gas is faster, implying that the lighter gas would diffuse faster than the heavier gas.
  • Some participants affirm the correctness of the formula but seek clarification on how it is being applied in the specific context of the problem.
  • There is a request for the numerical answer derived from the application of the formula, indicating a focus on the process rather than the final result.
  • One participant expresses concern about the answer not matching the provided choices, suggesting potential issues with the application of the formula or the assumptions made.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the formula being discussed, but there is uncertainty regarding its application and the resulting answer. Multiple viewpoints on the implications of gas properties and diffusion rates are present, indicating that the discussion remains unresolved.

Contextual Notes

Participants have not fully detailed their assumptions or the specific steps taken in their calculations, which may affect the clarity of the discussion.

rocomath
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A sample of an unknown gas takes 434 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) takes 175 s to diffuse through the same plug. What is the molar mass of the unknown gas?

[tex]\frac {Rate_{A}}{Rate_{B}} = \sqrt {\frac {\mathcal{M}_{B}}{\mathcal{M}_{A}}}[/tex]
 
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faster vs slower gas

which one is the faster gas? would the faster gas be the lighter or heavier gas?

try your equn this way

faster gas = sqrt (Mslower/Mfaster)
slower gas
 
Yes the formula is correct but how are you using it? That is show what your getting
 
ace123 said:
Yes the formula is correct but how are you using it? That is show what your getting
thanks, the answer doesn't even appear as one of the choices.
 
what did you get as an answer?
 
Last edited:
eli64 said:
what did you get as an answer?
i appreciate your help but i was really only concerned about the equation, thanks.
 

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