Digital Elevator: Designing a 2 Floor System

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    Digital Elevator
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The discussion focuses on designing a two-floor elevator system using an H-bridge for motor control. Key requirements include ensuring the elevator stops at both floors and only moves up when at the bottom and down when at the top. A proposed solution involves using reed switches placed on each floor to detect the elevator's position, allowing for polarity changes in the motor's power leads. Logic gates are suggested for implementing the stopping mechanism, with conditions defined through switches and resistors to manage the elevator's movement. The conversation emphasizes the importance of correctly configuring the reed switches to ensure proper operation.
JasonJo
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hey guys I am stumped on this project: make a 2 floor elevator. i am going to use an H-bridge to control which way the motor spins (ie. clockwise will make the elevator go up, counter - down).

anyway, here are the initial conditions to be met:
elevator must stop at both floors
elevator will only go up when it is down
elevator will only go down when it is up

any ideas to implement this? the class i am taking has no gone over microcontrollers, the farthest I've gone is MUX/DeMUX's.

PLEASE HELP!
 
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Please stop it with the please help bit.
I will help (i am nice coder after all)
put two reed switches on the track (one on each floor) and a magnet on the back of the car(the thingy which goes up and down), insetad of a h-bridge, just connect the power leads in differing polatities using the reed switches.

+ --_
sw1---_
sw2---------- lead 1
- --
- --_
sw1---_
sw2--------moveswitch-- lead 2
+ --

This should work, just don't mix up the two reed switches! (put them so that they engage only after they move to the floor)

Any questions so far?
 
how would it stop?
 
Simple logic gates.

Write out the conditions using some sort of switch (like the reed or a simple contact switch) with a resistor to pull logic high/low. Then its simply "up switch AND elevator at floor 1 switch" stuff, and you could write out the truth tables to show your work.

Cliff
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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