Dilution: 18-2wt% Solution | Calculate Volume

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Discussion Overview

The discussion revolves around the dilution of an 18 wt% solution to achieve a final concentration of 2 wt%. Participants are exploring the calculations involved in this dilution process, including the use of the formula C1 V1 = C2 V2.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant seeks assistance in calculating the volume of the 18 wt% solution needed to create a 2 wt% solution, mentioning confusion in their calculations.
  • Another participant points out the necessity of knowing or assuming the initial or final volume to proceed with the calculations.
  • A participant provides a calculation attempt, stating that 18% of 1g is 180mg and applies the dilution formula, arriving at a volume of 0.11 ml, which they express doubts about being too low.
  • There is a question regarding the conversion of 2 mg/mL to a percentage, indicating a potential misunderstanding of the units involved.
  • A clarification is made that the participant meant to refer to 2 wt% for the final solution, not 2 mg/mL.
  • Another participant questions whether 2 mg/mL is equivalent to 2 wt%, suggesting a need for further clarification on the definitions used.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the calculations and definitions of weight percentage versus concentration in mg/mL, and it remains unresolved as participants seek clarification and further input.

Contextual Notes

There are limitations in the assumptions made regarding initial and final volumes, as well as potential misunderstandings about the relationship between weight percentage and concentration units.

Who May Find This Useful

Individuals interested in solution preparation, dilution calculations, or those studying chemistry and related fields may find this discussion relevant.

flatpro
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Hey,

I have a solution of 18 wt % (about 1g/ml) I want to make it into a solution of 2 wt % by diluting it with water. Using C1 V1 = C2 V2 could someone show me how to do it. I have tried but seem to be getting muddled somewhere.

Thanks!
 
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You need to know (or assume) initial (or final) volume.

Show what you did, we will start from there.

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Final desired volume 10ml

18% of 1g = 180mgC1 V1 = C2 V2
(180mg/ml)(X) = (2mg/ml) (10ml)
X = 2 (10) / 189
X = 0.11 ml <--- which seems too low
 
Why 2 mg/mL?

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I mean 2 wt percentage of the final solution
 
Perhaps that's what you mean, but does 2 mg/mL equal 2%?

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methods
 

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