Simple solutions question (dilution)

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SUMMARY

The discussion centers on calculating the final concentration of a diluted Fe3+ solution after treatment with SCN- to form a complex. The initial concentration of the Fe3+ solution is 0.0007 mol/L, and 3 mL of this solution is diluted to a final volume of 100 mL. The relevant equation for dilution, C1*M1 = C2*M2, is applicable, but the formation of the complex may influence the final concentration. Participants emphasize the need to consider the moles of the target compound and the presence of excess thiocyanate ions.

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  • Understanding of molarity and dilution equations (C1*M1 = C2*M2)
  • Knowledge of complex ion formation in solution
  • Familiarity with stoichiometry and moles
  • Basic chemistry concepts related to ions and their interactions
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Homework Statement




Hi. If I have 3 mL of a Fe3+ solution (0.0007 mol/L) and that is treated with SCN- to form a complex and then is diluted until I have 100 mL of a solution.

What would be the final concentraton of that solution?

Homework Equations



C1*M1= C2*M2

The Attempt at a Solution



I Thought of the equation above, but I know that the formation of that comple must change something!
 
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Rujano said:
What would be the final concentraton of that solution?

Concentration of what? You have several ions present (I can list about a dozen, but you don't have to know about most of them).
 
How many moles of your target compound or ion? What final volume is the solution? Molarity is moles per Liter. Is thiocyanate ion added in excess of the ferric ion?
 

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