Dimension of row/ column space

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SUMMARY

The discussion focuses on verifying that the row rank is equal to the column rank of the matrix A = [1 2 1; 2 1 -1]. Participants emphasize the importance of row reducing the matrix to row echelon form to determine the ranks explicitly. Key steps include demonstrating that the rows are not linear combinations of each other and that one column is a linear combination of the other two columns. This leads to the conclusion that rank(A) equals both the row rank and column rank.

PREREQUISITES
  • Understanding of matrix row echelon form
  • Knowledge of linear combinations in vector spaces
  • Familiarity with the concepts of row rank and column rank
  • Basic proficiency in matrix operations
NEXT STEPS
  • Learn about Gaussian elimination for row reduction
  • Study the properties of vector spaces and linear independence
  • Explore the concept of rank in linear algebra
  • Investigate applications of rank in solving systems of equations
USEFUL FOR

Students studying linear algebra, educators teaching matrix theory, and anyone interested in understanding the fundamental concepts of row and column spaces in matrices.

jeffreylze
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Homework Statement



In the following exercises verify that the row rank is equal to the column rank by explicitly finding the dimensions of the row space and the column space of the given matrix.

A = [1 2 1 ; 2 1 -1]


Homework Equations





The Attempt at a Solution



All i can think of is just row reduce it to row echelon form and then find the rank of the matrix. How do i do it explicitly?
 
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1. Show that the rows of A are not linear combinations of each other, i.e. one is the multiple of the other.

2. Show that one column is the linear combination of the other 2 columns. Then show that the remaining 2 columns are not a multiple of the other.

then you've explicitly shown that the rank(A) = row rank (A) = column rank (A)
 
hokie1 said:
1. Show that the rows of A are not linear combinations of each other, i.e. one is the multiple of the other.

2. Show that one column is the linear combination of the other 2 columns. Then show that the remaining 2 columns are not a multiple of the other.

then you've explicitly shown that the rank(A) = row rank (A) = column rank (A)

Do you mean by one is NOT the multiple of the other?
 
You are quite correct. I did not proofread before submitting.
 
Okay, thanks. Now that make sense =D
 

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