How Many Milligrams of Fluoride Are in 8 Cups of Water?

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SUMMARY

The discussion focuses on calculating the amount of fluoride in 8 cups of water, given a concentration of 1.00 part per million (ppm) by mass. To determine the fluoride content, one must first convert the volume of water into mass using the density of water, which is 1.00 g/cm3. After calculating the mass of the water, the fluoride content can be found by dividing the mass of water by 1,000,000 to obtain the mass of fluoride in milligrams.

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  • Understanding of parts per million (ppm) concentration
  • Basic knowledge of density and mass conversion
  • Familiarity with metric units, specifically grams and milliliters
  • Ability to perform unit conversions between volume and mass
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  • Learn how to convert volume measurements to mass using density
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Students in chemistry or nutrition fields, educators teaching concentration calculations, and anyone interested in understanding fluoride levels in drinking water.

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Homework Statement


Nutrition experts recommend that you drink at least 8 cups of water daily. If your local water supply contains 1.00 part fluoride (by mass) per million parts water, how many milligrams of fluoride would you consume daily in your 8 cups of water? (use 1.00 g cm^-3 as the density of water)


Homework Equations





The Attempt at a Solution


I just don't know how to set this up. I tried putting 1.00 part fluoride over 1 million parts water, but that just made a mess. Fluoride is in parts and I have to convert that to milligrams. I'm lost on how to do that.

Thanks.
 
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1 ppm of F by mass just means that for any mass of water, the mass of fluoride present in it will be one millionth that.

So all you have to do is calculate the mass of water present, and then divide that by 106 to get the mass of fluoride in that water.

EDIT: Since the density of water is given in cgs units, you'll have to convert the given volume of water to cgs units.
 

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