Dimensional analysis to determine unknown exponents

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SUMMARY

The forum discussion focuses on using Dimensional Analysis to determine the unknown exponents in the equation \(\lambda = k \mu^{l} f^{m} T^{n}\). The established exponents are l = -1/2, m = -1, and n = 1/2. The dimensions of the variables are correctly identified as \(\lambda = [L]\), \(f = [L]^{-1}\), \(T = [M][L][T]^{-2}\), and \(\mu = [M][L]^{-1}\). The user successfully sets up a system of equations based on dimensional consistency to solve for the exponents.

PREREQUISITES
  • Understanding of Dimensional Analysis
  • Familiarity with basic physics concepts such as wavelength, frequency, tension, and mass per unit length
  • Knowledge of algebraic manipulation and solving systems of equations
  • Basic understanding of dimensional units ([L], [M], [T])
NEXT STEPS
  • Study the principles of Dimensional Analysis in physics
  • Learn how to derive relationships between physical quantities using dimensional equations
  • Practice solving systems of linear equations in multiple variables
  • Explore applications of Dimensional Analysis in various fields such as fluid dynamics and mechanics
USEFUL FOR

Students in physics, educators teaching dimensional analysis, and anyone interested in solving equations involving physical quantities and their relationships.

Vasili
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Homework Statement


1. Use the method of Dimensional Analysis to show that the unknown exponents in Equation (1) are l=-1/2, m=-1, and n=1/2.

Homework Equations


Equation (1) is \lambda = k \mu ^{l} f ^{m} T^{n}

Where:
\lambda is the wavelength;
f is the frequency of the sound;
T is the tension in the string;
\mu is the mass per unit length of the string.
k is a dimensionless constant.

The Attempt at a Solution


The dimensions for the above terms should be:
\lambda = [L] (Simple enough)
f=[L] ^{-1} (Since the frequency is the inverse of time. Is this correct?)
T=[M][L][T] ^{-2} (Since the tension in the rope is just the force exerted on it, right?)
\mu = [M][L] ^{-1} (Since it is the mass per unit length)

Which gives the dimensional equation as:
[L]=([M] \cdot [L]^{-1}) ^{l} \cdot ([T] ^{-1}) ^{m} \cdot ([M] \cdot [L] \cdot [T]^{-2})^{n}

Which can be used to make equations for [L], [T], and [M], respectively:

1=-1l + 1n ([L]) (i)
0=-1m - 2n ([T]) (ii)
0=1l + 1n ([M]) (iii)

And from here I don't know where to go. If I manipulate (ii) to state n in terms of m, I get n=-1/2m. But where do I go from here? I need to solve these three equations simultaneously?
 
Last edited:
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Oh, I got it. Sorry, I keep doing this with my posts here. XD
 

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