Dipole moment of an isolated quantum system

Click For Summary
SUMMARY

The dipole moment of an isolated quantum system in isotropic space is zero unless accidental degeneracy occurs. This conclusion is supported by the symmetry of the ground state, which remains unaffected by space inversion, leading to the expectation value of the electric dipole being equal to its negative. The discussion references Philip Anderson's insights on symmetry breaking, particularly in relation to ferroelectrics and their non-eigenstate behavior, which results in quantum superpositions that yield a net dipole moment of zero. This understanding is crucial for comprehending the emergence of new physical laws in complex systems.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of electric dipole moments
  • Knowledge of symmetry and parity in physics
  • Familiarity with quantum superposition principles
NEXT STEPS
  • Study Philip Anderson's paper "More Is Different" for insights on symmetry breaking
  • Explore the implications of parity invariance in quantum systems
  • Research the behavior of ferroelectrics in quantum mechanics
  • Investigate the concept of accidental degeneracy in quantum states
USEFUL FOR

Physicists, quantum mechanics researchers, and students studying the implications of symmetry and dipole moments in isolated quantum systems.

Sheldon Cooper
Messages
21
Reaction score
0
How to prove the dipole moment of an isolated quantum system in isotropic space is identically equal to zero, unless there exists an accidental degeneracy.

Thanks in advance
 
Physics news on Phys.org
Do you mean electric dipole or any dipole (I know of three)?

Assuming you mean electric dipole, is your statement true? Is a piece of ferroelectic in vacuum an isolated quantum system? Afterall, it could have electric dipole moment?

For simple systems, like particles I think the argument usually boils down to ground-state being symmetric, and therefore unaffected by space inversion, whereas electric dipole being a polar vector and therefore affected by space inversion, thus the expectation value for the electric dipole has to be equal to its negative self -> it's zero.
 
Cryo said:
Assuming you mean electric dipole, is your statement true? Is a piece of ferroelectic in vacuum an isolated quantum system? Afterall, it could have electric dipole moment?

As an aside, the example of an electric dipole moment in was precisely what Philip Anderson used in his famous paper "More Is Different" to demonstrate the notion of the emergence of new laws of physics and symmetry breaking in complex systems. He had learned in a nuclear physics course in graduate school that no stationary state in a parity invariant theory has a net electric dipole moment, which confused him because there seem to be numerous examples to the contrary away from nuclear physics. His thinking on this led him to important insights about how symmetry can be spontaneously broken in quantum systems (he was one of the pioneers of understanding symmetry breaking in physics).

The resolution is that the ferroelectric is not actually in an eigenstate. The true eigenstates are the two quantum superpositions of the states with equal/opposite dipole moments (and therefore zero dipole moment)*, and there is some time period (probably much longer than the age of the universe) for the rotation of the macroscopic dipole moment. This classic paper by Anderson on symmetry breaking in antiferromagnets was the first detailed description of this phenomenon.

* Here I'm assuming that we can ignore parity-violating effects in particle physics for the purposes of describing stable matter.
 
  • Like
Likes   Reactions: Cryo

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
784
  • · Replies 3 ·
Replies
3
Views
3K
Replies
5
Views
1K
  • · Replies 48 ·
2
Replies
48
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
17
Views
3K