Classical magnetic dipole-dipole interaction in iron

In summary, you seem to have trouble understanding the physics of the dipole-dipole interaction in an ideal classical system. You have several doubts about how this system would work.
  • #1
rogdal
14
2
Homework Statement
A magnetic dipole μ, which is located at the origin of a coordinate system, generates a magnetic field in its environment given by:

$$\vec{B}(\vec{r})=\frac{\mu_0}{4\pi}\frac{3(\vec{\mu}·\vec{r})\vec{r}-r^2\vec{\mu}}{r^5}$$

Calculate the magnetic field B generated by an atom with a magnetic moment μ ≃ μB (Bohr magneton) at the position of a neighbouring atom in iron. The typical first-neighbour distance r0 for Fe ferromagnets can be calculated knowing that Fe has a bcc lattice with a = 2.866 ̊A.
Relevant Equations
$$\vec{B}(\vec{r})=\frac{\mu_0}{4\pi}\frac{3(\vec{\mu}·\vec{r})\vec{r}-r^2\vec{\mu}}{r^5}$$

In a BCC lattice, ##r_0 = \frac{\sqrt{3}}{2}a##
I'm having a bit of trouble with this exercise because, even if I understand the physics of the dipole-dipole interaction in an ideal classical system, I don't get to know how to approach this problem. I've got a few doubts about how this system would work.

First of all, what would be the direction of the magnetic moment ##\vec{\mu}## of iron with respect to its lattice? I guess that by simplicity the direction [100] should be chosen, but I don't know if each atom's magnetic moment has the same direction.

Besides, now assuming ##\vec{\mu}## is fixed, the value of B wouldn't be the same in all the first neighbours positions, right? Since it depends on the dot product between the magnetic moment and the first neighbour's position, and this wouldn't be the same for the atom in the upper left corner and the one in the bottom right.

Do you know how to approach this exercise?

Thank you!
 
Physics news on Phys.org
  • #2
You seem to worry about dipole-dipole interaction. But the problem states magnetic field caused by a dipole at the place of another dipole. You do not have to worry about the direction of the dipole at that place.
 
  • #3
anuttarasammyak said:
You seem to worry about dipole-dipole interaction. But the problem states magnetic field caused by a dipole at the place of another dipole. You do not have to worry about the direction of the dipole at that place.
Really? Well, in reality I worry about the direction of the dipole that is causing the magnetic field, i.e., the one in the origin of coordinates. Wouldn't its direction influence the product ##\vec{\mu}·\vec{r}##?
 
  • #4
rogdal said:
Wouldn't its direction influence the product μ→·r→?
Yes, the inner product matters. For an examle you may set r coordinates according to crystal structure and place a dipole in its origin and you can rotate dipole as you like which changes B at (1,0,0) for an example.

After you got it you may be able to proceed to next story of B##\mu_2## energy at (1,0,0) to estimate ##\mu_1## dipole-##\mu_2## dipole interaction.
 
Last edited:
  • #5
anuttarasammyak said:
Yes, the inner product matters. For an examle you may set r coordinates according to crystal structure and place a dipole in its origin and you can rotate dipole as you like which changes B at (1,0,0) for an example.

But if I did what you say I'd have, for instance, ##\vec{r}=(1,0,0)##. Then the total magnetic field would be:

$$\vec{B}=\frac{\mu_0}{4\pi}\left(3(\mu\cos{\theta})\hat{u_x}-\vec{\mu}\right)$$

Since ##|\vec{r}|=1##. But this expression cannot be simplified because we don't know what the direction of ##\vec{\mu}## is.

Is that what you mean?

And then, I could get the dipole-dipole energy. But, assuming ##\vec{\mu_1}## and ##\vec{\mu_2}## are parallel, then their specific directions wouldn't be needed, right?

Thanks for the help!
 
Last edited:
  • #6
It is also written as
[tex]\vec{B}(1,0,0)=\frac{\mu_0}{4\pi}(3\mu_x\hat{u_x}- \vec{\mu})[/tex]
##\vec{\mu}=(\mu_x,\mu_y,\mu_z)## is a parameter. It depends on direction of ##\vec{\mu}## as you suspect. Interaction energy with another dipole at (1,0,0) is
[tex]\vec{\mu_2}\cdot\vec{B}(1,0,0)=\frac{\mu_0}{4\pi}(3\mu_{1x}\mu_{2x}- \vec{\mu_1}\cdot\vec{\mu_2})[/tex]
 
Last edited:
  • Like
Likes rogdal
  • #7
Ah, I see. I thought the exercise was meant to obtain a well defined expression of ##\vec{B}## in terms of the Bohr magneton.

Thanks!
 
  • #8
It is interesting to look at the geometry and the minimum and maximum values (although usually one looks at energies rather than forces)
You do need to specify the relative orientation of the electron magnetic moments. Of course in a real chunk of iron the interaction of an electron spin with all of its neighbors is a very interesting problem that results in creation of self organizing magnetic domains. These magnetic domains are are also influenced by the geometry of the crystaline structure, not to mention the temperature (see Curie Temp) among other thinngs . Lotsa physics here.
 
  • Like
Likes PhDeezNutz and rogdal

1. What is classical magnetic dipole-dipole interaction in iron?

Classical magnetic dipole-dipole interaction in iron refers to the force between two magnetic dipoles in iron. It is a fundamental electromagnetic force that arises due to the alignment of the magnetic moments of individual atoms in iron.

2. How does classical magnetic dipole-dipole interaction in iron affect the material?

The interaction between magnetic dipoles in iron results in the alignment of the magnetic moments of individual atoms, leading to the formation of magnetic domains. This results in the overall magnetic properties of iron, such as its ability to be magnetized and its magnetic strength.

3. What factors affect the strength of classical magnetic dipole-dipole interaction in iron?

The strength of classical magnetic dipole-dipole interaction in iron depends on the distance between the two dipoles, the orientation of the dipoles, and the magnetic susceptibility of the material. It also depends on the strength of the external magnetic field.

4. How is classical magnetic dipole-dipole interaction in iron different from other types of magnetic interactions?

Classical magnetic dipole-dipole interaction is a long-range force that is dependent on the distance between the dipoles, whereas other types of magnetic interactions, such as exchange interaction, are short-range forces that are dependent on the arrangement of atoms in a material. Classical magnetic dipole-dipole interaction is also a fundamental electromagnetic force, while other types of magnetic interactions arise from quantum mechanical effects.

5. What are the practical applications of classical magnetic dipole-dipole interaction in iron?

Classical magnetic dipole-dipole interaction in iron is the basis for many important technologies, such as magnetic storage devices, electric motors, and generators. It is also used in magnetic resonance imaging (MRI) machines for medical diagnosis and in magnetic sensors for various industrial and scientific applications.

Similar threads

  • Advanced Physics Homework Help
Replies
17
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
230
Replies
1
Views
642
  • Introductory Physics Homework Help
Replies
1
Views
349
  • Introductory Physics Homework Help
Replies
25
Views
276
  • Advanced Physics Homework Help
Replies
1
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
204
  • Advanced Physics Homework Help
Replies
1
Views
918
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
7K
Back
Top