# A Dirac Delta and Residue Calculus

1. May 7, 2017

### Daniel Gallimore

I'm an undergraduate student, so I understand that it may be difficult to provide an answer that I can understand, but I have experience using both the Dirac delta function and residue calculus in a classroom setting, so I'm at least familiar with how they're applied.

Whether you're integrating along a closed loop around a singularity in the complex plane or you're integrating on a closed sphere in 3D space about a Dirac delta (like you might do in E&M), the value of the integral depends entirely on the point where the singularity/delta is located. Do these similarities betray a connection between the Dirac delta and residue calculus?

2. May 8, 2017

### stevendaryl

Staff Emeritus
Well, I would say that there is a closer connection between residues and the Heaviside function $H(x)$ defined as follows:

$H(x) = 0$ if $x < 0$
$H(x) = 1$ if $x > 0$

Then an integral representation of $H(x)$ is:

$H(x) = lim_{\epsilon \rightarrow 0} \frac{1}{2\pi i} \int_{-\infty}^{+\infty} \frac{1}{\tau -i \epsilon} e^{ix\tau} d\tau$

which you can prove using residues.

$H(x)$ is related to the delta-function by formally taking the derivative of this integral representation with respect to $x$:

$\delta(x) \equiv \frac{dH}{dx} = lim_{\epsilon \rightarrow 0} \frac{1}{2\pi i} \int_{-\infty}^{+\infty} \frac{i \tau}{\tau -i \epsilon} e^{ix\tau} d\tau$
$= \frac{1}{2\pi} \int_{-\infty}^{+\infty} e^{ix\tau} d\tau$

3. May 8, 2017

### zwierz

It is hard to encounter adequate understanding of the distributions concept in physical textbooks.
Try
KöSaku Yosida. Functional Analysis. Sixth Edition. Springer-Verlag. Berlin Heidelberg New York 1980

4. May 8, 2017

### zwierz

it just remains to explain what this divergent integral means and in which sense the limit $\epsilon\to 0$ is understood