Math Amateur
Gold Member
MHB
- 3,920
- 48
I am reading John Dauns book "Modules and Rings". I am having problems understanding the notation in section 1-2 (see attachment)
My issue is understanding the notation on Section 1-2, subsection 1-2.1 (see attachment).
Dauns is dealing with the product \Pi \{ M_i | i \in I \} \equiv \Pi M_i and states in (ii) - see attachment
------------------------------------------------------------------------------------------------------
Alternatively, the product can be viewed as consisting of all strings or sets
x = \{ x_i | i \in I \} \equiv (x_i)_{i \in I} \equiv (x_i) \equiv ( \_ \_ \_ \ , x_i , \_ \_ \_ ) , x_i \in M_i; i-th
-----------------------------------------------------------------------------------------------------------
I am not sure of the meaning of the above set of equivalences. Can someone briefly elaborate ... preferably with a simple example
If we take the case of I = {1,2,3} and consider the product M_1 \times M_2 \times M_3 then does Dauns notation mean
x = (x_1, x_2, x_3) where order in the triple matters (mind you if it does what are we to make of the statement x = \{ x_i | i \in I \}Can someone confirm that x = (x_1, x_2, x_3) is a correct interpretation of Dauns notation?
===============================================================================================
Dauns then goes on to define the direct sum as follows:
The direct sum \oplus \{ M_i | i \in I \} \equiv \oplus M_i is defined as the submodule \oplus M_i \subseteq \Pi M_i consisting of those elements x = (x_i) \in \Pi M_i having at most a finite number of non-zero coordinates or components. Sometimes \oplus M_i , \Pi M_i are called the external direct sum and the external direct product respectively.================================================================================================
Can someone point out the difference between \oplus M_i , \Pi M_i in the case of the example involving M_1, M_2, M_3 - I cannot really see the difference! For example, what elements exactly are in \Pi M_i that are not in \oplus M_i
I would be grateful if someone can clarify these issues.
Peter
This has also been posted on MHF
My issue is understanding the notation on Section 1-2, subsection 1-2.1 (see attachment).
Dauns is dealing with the product \Pi \{ M_i | i \in I \} \equiv \Pi M_i and states in (ii) - see attachment
------------------------------------------------------------------------------------------------------
Alternatively, the product can be viewed as consisting of all strings or sets
x = \{ x_i | i \in I \} \equiv (x_i)_{i \in I} \equiv (x_i) \equiv ( \_ \_ \_ \ , x_i , \_ \_ \_ ) , x_i \in M_i; i-th
-----------------------------------------------------------------------------------------------------------
I am not sure of the meaning of the above set of equivalences. Can someone briefly elaborate ... preferably with a simple example
If we take the case of I = {1,2,3} and consider the product M_1 \times M_2 \times M_3 then does Dauns notation mean
x = (x_1, x_2, x_3) where order in the triple matters (mind you if it does what are we to make of the statement x = \{ x_i | i \in I \}Can someone confirm that x = (x_1, x_2, x_3) is a correct interpretation of Dauns notation?
===============================================================================================
Dauns then goes on to define the direct sum as follows:
The direct sum \oplus \{ M_i | i \in I \} \equiv \oplus M_i is defined as the submodule \oplus M_i \subseteq \Pi M_i consisting of those elements x = (x_i) \in \Pi M_i having at most a finite number of non-zero coordinates or components. Sometimes \oplus M_i , \Pi M_i are called the external direct sum and the external direct product respectively.================================================================================================
Can someone point out the difference between \oplus M_i , \Pi M_i in the case of the example involving M_1, M_2, M_3 - I cannot really see the difference! For example, what elements exactly are in \Pi M_i that are not in \oplus M_i
I would be grateful if someone can clarify these issues.
Peter
This has also been posted on MHF