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Miike012 said:My solution
d. [itex]\forall x[/itex] [itex]\exists y[/itex](F(x)^S(y) → [itex]\neg A(y,x)[/itex])
e. [itex]\exists x[/itex] [itex]\forall y[/itex](F(x)^S(y) → [itex]\neg A(y,x)[/itex])
f.[itex]\exists x[/itex] [itex]\forall y[/itex](S(x)^F(y) → A(x,y))