Discover the Initial Acceleration of a Stone Stuck in a Car's Tire Groove

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SUMMARY

The discussion centers on the initial acceleration of a stone that becomes lodged in a car tire groove as the vehicle travels at a constant velocity. The consensus is that the initial acceleration of the stone is vertically upward due to the centripetal force acting on it as it exits the road surface. If the car were accelerating forward instead of maintaining a constant velocity, the stone's acceleration would be a combination of upward and forward components, approximating a 45° angle to the horizontal. Thus, the correct answer under constant velocity is (A) vertically upward.

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A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial acceleration of the stone, as it leaves the surface of the road, is
(A) vertically upward
(B) horizontally forward
(C) horizontally backward
(D) zero
(E) upward and forward, at approximately 45° to the horizontal




I think it's A because as it leaves the surface of the road it is on the bottom of the circle, and centripetal force points vertically up. Is this correct?
 
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That looks fine to me, however; if the car was accelerating forwards and not traveling at a constant velocity, you can see that there would be vehicular acceleration as well as centripetal acceleration such that the answer would look a lot more like E.
 

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