Discover the Truth Behind Relative Maximums: A Simple Max/Min Question

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Homework Help Overview

The discussion revolves around understanding the conditions for identifying relative maximums and minimums using the second derivative test in calculus. Participants are examining the implications of the second derivative's sign at critical points.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the conditions under which a critical point is classified as a relative maximum or minimum based on the second derivative. Some participants question the validity of the statements presented, while others provide examples to illustrate the concepts.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the second derivative test. Some guidance has been offered through examples, but there is no explicit consensus on the original poster's questions.

Contextual Notes

The original poster mentions being pressed for time and refers to notes taken for an upcoming test, indicating a sense of urgency in seeking clarification.

duki
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When given a table listing x, x', and x'' which of the following are true?

if at critical #, second derivative is negative, # is a relative max
if at critical #, second derivative is positive, # is a relative max

Thanks!
 
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These are yes or no questions. Read your book!
 
sorry, I know it seems like I'm not trying.
I was reviewing notes for a test tomorrow and in one section I wrote the first one and then right below it I wrote the second one. If I weren't so pressed on time I would find it in my book but I'm really trying to get finished and get a good nights sleep. D:
 
Remember this. y=x^2. Second derivative=2. x=0 is a min. y=-x^2. Second derivative=(-2). x=0 is a max.
 
all right! thanks.
 

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