MHB Discovering Rational Roots for Simplifying Polynomials

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The discussion focuses on techniques for simplifying the polynomial x^3 - 9x^2 + 27x - 27. Participants explore using the expansion of (a + b)^3 to identify that the polynomial can be factored as (x - 3)^3, indicating that 3 is a root. There is also a mention of the rational root theorem, which suggests possible rational roots of ±1, ±3, ±9, and ±27. The conversation emphasizes the importance of practice in recognizing patterns in polynomial simplification. Overall, the exchange highlights collaborative problem-solving in mathematics.
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I wonder what are the tecniques,or what is the easiest way to simplify given polynomial:

$$x^3-9x^2+27x-27$$

If possible,without Horners algorithm. Thank you!
 
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Perhaps if you write it as:

$$x^3+3x^2(-3)+3x(-3)^2+(-3)^3$$

Does this look like a familiar expansion?
 
MarkFL said:
Perhaps if you write it as:

$$x^3+3x^2(-3)+3x(-3)^2+(-3)^3$$

Does this look like a familiar expansion?

Yes MArk,but what is the next step?
What should i do with $$3^n$$ terms?
 
wishmaster said:
Yes MArk,but what is the next step?
What should i do with $$3^n$$ terms?

Consider that:

$$(a+b)^3=a^3+3a^2b+3ab^2+b^3$$

What are $a$ and $b$ in the case of the given expression?
 
MarkFL said:
Consider that:

$$(a+b)^3=a^3+3a^2b+3ab^2+b^3$$

What are $a$ and $b$ in the case of the given expression?

$a$ is $x$ and $b$ is $-3$ ?
 
wishmaster said:
$a$ is $x$ and $b$ is $-3$ ?

Yes, that's correct! :D

So, what is the factored form?
 
MarkFL said:
Yes, that's correct! :D

So, what is the factored form?

$$(x-3)^3$$ so the root of the polynomial is $3$.

I can't switch my brains to mathematical thinking...i get stucked by easy problems like this,and that is no good...
 
wishmaster said:
$$(x-3)^3$$ so the root of the polynomial is $3$.

I can't switch my brains to mathematical thinking...i get stucked by easy problems like this,and that is no good...

It comes with practice...you will find the more practice and experience you have, the more quickly you recognize patterns you have seen before. :D
 
MarkFL said:
It comes with practice...you will find the more practice and experience you have, the more quickly you recognize patterns you have seen before. :D

Yes,i think so...actually,i have no books,or something to learn,only online help. So here on the forum, and especially you MArk,are very helpfull for me...
 
  • #10
wishmaster said:
Yes,i think so...actually,i have no books,or something to learn,only online help. So here on the forum, and especially you MArk,are very helpfull for me...

We are glad to help here at MHB. :D

Also, I forgot to mention that your factored form is correct. (Yes)
 
  • #11
MarkFL said:
We are glad to help here at MHB. :D

Also, I forgot to mention that your factored form is correct. (Yes)

Thank you!

Yes,its correct,but I am not happy beacuse i didnt come alone to the solution...
 
  • #12
wishmaster said:
Thank you!

Yes,its correct,but I am not happy beacuse i didnt come alone to the solution...

Try another method then. Pretend you don't know the answer, and see if you can instead apply the rational roots theorem.
 
  • #13
MarkFL said:
Try another method then. Pretend you don't know the answer, and see if you can instead apply the rational roots theorem.

Wish i could know the other method...
 
  • #14
wishmaster said:
Wish i could know the other method...

Here is an article on it:

Rational root theorem - Wikipedia, the free encyclopedia

This theorem tells us that if the given polynomial has rational roots, it will come from the list:

$$\pm\left(1,3,9,27 \right)$$

So we let:

$$f(x)=x^3-9x^2+27x-27$$

and when we find a number $k$ from the list such that:

$$f(k)=0$$

then we know $x-k$ is a factor, and we may use polynomial or synthetic division to get:

$$f(x)=(x-k)P(x)$$

And then we see if we can then further factor $P(x)$.
 
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