- #1

kasse

- 384

- 1

1/(16n^2-8n-3)

I want to find the sum of this series from n=1 to infinity

By partial fraction I find

1/(16n^2-8n-3)=1/((4n+3)(4n-1))

which can be written

(1/4)(1/(4n-1)-1/(4n+3))

The sum of this is 1/12, but the right answer is 1/4. What is wrong?

I want to find the sum of this series from n=1 to infinity

By partial fraction I find

1/(16n^2-8n-3)=1/((4n+3)(4n-1))

which can be written

(1/4)(1/(4n-1)-1/(4n+3))

The sum of this is 1/12, but the right answer is 1/4. What is wrong?

Last edited: