Displacement of ball bearing using conservation of energy

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Homework Help Overview

The problem involves a ball bearing suspended as a pendulum, released from a height and subsequently falling while traveling horizontally. The relationship between the height and the horizontal displacement is questioned, particularly the derivation of the equation D^2=4hL.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy principles to relate potential and kinetic energy, and question how the height and horizontal distance are interconnected. Some suggest breaking the problem into two stages of motion: falling through height h and then through height L.

Discussion Status

There is an ongoing exploration of the relationship between the variables involved, with participants providing insights into the mechanics of projectile motion and the effects of time on horizontal displacement. No consensus has been reached regarding the derivation of the equation or the dependencies of the variables.

Contextual Notes

Participants are considering the implications of varying heights and the time of flight on horizontal displacement, raising questions about the assumptions made in the problem setup.

phosgene
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Homework Statement



A large ball bearing is suspended as a pendulum. One end of the pendulum is held by the electromagnet (1) and the ball is initially held by magnet (2) at some height, h, above its lowest position. The ball is released from (2) and as the pendulum swings through the vertical, the ball cuts an infrared beam (3) and causes the electromagnet holding the string (1) to release it. Ideally, the string is released at the instant the ball cuts the infrared beam. The ball then falls a height L and travels a horizontal distance D from the point of release.

The final displacement (D) of the ball from the release point can be determined using:

D^2=4hL

I can't figure out how this was derived.

physics1.png


Homework Equations



Potential energy = mgh
Kinetic energy = \frac{1}{2}mv^2

The Attempt at a Solution



I really have no idea. I thought that the final displacement from the release point would be dependent only on h, as the force of gravity after release is only acting downwards, so the horizontal velocity wouldn't change. I've also tried 'reverse-engineering' the equation to figure out how it was derived, but I don't understand where the L*h value came from, as the final kinetic energy should be mg(L+h).
 
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The velocity of the ball is horizontal at point 3 and you get it from conservation of energy. mgh=1/2 m v^2. After reaching point 3, the ball is a projectile.

ehild
 
Try the solution in two steps.
a) falling through h
b) falling through L.
 
phosgene said:
I thought that the final displacement from the release point would be dependent only on h, as the force of gravity after release is only acting downwards, so the horizontal velocity wouldn't change.

Ok, horizontal velocity doesn't depend on L, but what if L is very big, let's say 1 mile ?
The ball takes "a lot of" time before touching the ground and during that time it moves horizontally as well.
 
Quinzio said:
Ok, horizontal velocity doesn't depend on L, but what if L is very big, let's say 1 mile ?
The ball takes "a lot of" time before touching the ground and during that time it moves horizontally as well.

Yes it does..So where's the problem?
 

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