- #1
ComptonFett
- 8
- 0
I can quickly calculate the dissociation degree of a monoprotic acid with the formula below (derived from the Hendersson-Hasselbach equation). I don't see any reason why this would not work also for polyprotic acids but I would like to confirm that it does. I would appreciate it if someone could confirm/disconfirm this. Thanks.
\begin{align}
& pH=pKa+\log \frac{A^{-}}{HA} \\
& \log \frac{A^{-}}{HA}=pH-pKa \\
& \frac{A^{-}}{HA}=10^{pH-pKa} \\
\end{align}
\begin{align}
& pH=pKa+\log \frac{A^{-}}{HA} \\
& \log \frac{A^{-}}{HA}=pH-pKa \\
& \frac{A^{-}}{HA}=10^{pH-pKa} \\
\end{align}