# Dissociation energy for the NO molecule

Hi,

Does anyone know where I can find post-hartree-fock calculation benchmarks for dissociation energy of the NO molecule. Or even just the equilibrium energy of the NO molecule?

I am looking for cc-pVTZ basis set results but I can only seem to find augmented basis set results.

Thanks.

I did a geometry optimisation in qchem at CCSD(T)/cc-pVTZ level. Hope this helps.
Z-matrix Print:
$molecule 0,2 1 N 2 O 1 1.154418$end
Final energy is -129.70273042654063

I did a geometry optimisation in qchem at CCSD(T)/cc-pVTZ level. Hope this helps.
Z-matrix Print:
$molecule 0,2 1 N 2 O 1 1.154418$end
Final energy is -129.70273042654063

That was fast! Thanks. How long did this calculation take? How many cores? It seems much faster than the method I was trying.

cgk
That was fast! Thanks. How long did this calculation take? How many cores? It seems much faster than the method I was trying.
This calculation should be a matter of seconds on a single core.

Note the horrific scaling of CCSD(T) (7th order). That means it gets very slow quickly for larger systems. That also means that it is very fast for small systems, like NO.

As a side note: The performance of different programs differs widely for different methods and basis sets. For example, many programs cannot deal well with generally contracted basis sets (like cc-pVnZ), and then it can easily happen that one program is spending two days calculating integrals where another program does the same job in five minutes...
So you generally want to use a program which is known to handle a certain kind of task well (e.g., Molpro is a good choice for coupled cluster calculations).

I think this computer has 4 cores, but as cgk said this calculation is fast for small systems. I also recommend cfour for cupled cluster calculations, its free of charge for non-commercial users :) http://www.cfour.de/

Interesting. Would either of you know how efficient a CCSDT, as opposed to CCSD(T) calculation would be? I ask because I have found a set of benchmarks, but I think they are using slightly tweaked basis sets (They optimise the polarisation exponent).