How to Determine the Wavelength to Cleave O-H Bonds in Water?

  • Thread starter Thread starter member 392791
  • Start date Start date
  • Tags Tags
    Bonds Radiation
Click For Summary

Discussion Overview

The discussion centers on determining the wavelength of light required to cleave O-H bonds in water, exploring the relationship between bond dissociation energy and wavelength, and the feasibility of using electromagnetic radiation for this purpose. The scope includes theoretical considerations, practical applications, and references to related scientific literature.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • One participant proposes using the bond dissociation energy of the O-H bond, calculated as 460 kJ/mole, and suggests that the total energy for two bonds would be 920 kJ/mole.
  • Another participant suggests considering bond strength per molecule rather than per mole, affirming that radiation can be used to cleave bonds.
  • A different participant notes that while cleaving bonds with electromagnetic radiation is possible, it is not practical in every case and references water radiolysis as a relevant example.
  • One participant expresses interest in using photolysis to break down water or hydrogen peroxide to form H2 and O2, seeking literature on the necessary wavelengths for bond cleavage without producing radicals.
  • Another participant questions whether the initial calculation for wavelength is appropriate, particularly regarding its relation to promoting electrons to higher energy orbitals.

Areas of Agreement / Disagreement

Participants express varying views on the feasibility and methods for cleaving O-H bonds with radiation, indicating that multiple competing perspectives remain without a clear consensus on the best approach or calculation method.

Contextual Notes

There are limitations regarding the assumptions made about bond dissociation energy and the applicability of the energy equation used. The discussion also highlights the complexity of using radiation for bond cleavage and the potential for side products in reactions.

Who May Find This Useful

Researchers and students interested in photochemistry, radiochemistry, and the practical applications of electromagnetic radiation in chemical bond cleavage may find this discussion relevant.

member 392791
Hello,

I was wondering how I could go about finding the wavelength of light that would cleave the O-H bonds of a water molecule.

I looked up the bond dissociation energy of the O-H bond, and it is 460 kJ/mole.

Now, since there are two O-H bonds, it should be twice as much, 920 kJ/mole.

Would the correct equation to use to find the wavelength to dissociate the bonds be

E = hc/λ?

That E is usually the energy to promote an electron to a higher energy level, but I wonder if it can be used in this case. When I did it, I found the wavelength to be on the order of 10^-25 meters, so something with a far lower wavelength than even a gamma ray. Is cleaving a chemical bond using radiation feasible?
 
Chemistry news on Phys.org
It may be better to consider bond strength per molecule, not per mole. But yes, radiation can be used to cleave bonds.
 
Cleaving bonds with EM radiation is possible, but not for every case and it is not always practical.

For your specific example you can look for papers dealing with water radiolysis. Gamma irradiated water is known to make radicals the infamous one being the hydroxyl radical, which is formally a homolytic cleavage of an OH bond.

More terms to use to learn about this type of thing would be photochemistry.
 
I am trying to figure out if I can use photolysis to break down water or some other compound (hydrogen peroxide) to form H2 and O2 without the radicals and other side products. Anyone have some literature of what I can do for this and what wavelength I need to cleave the bonds.
 
Also, is that calculation the proper way to find the wavelength with enough energy to cleave the bond. I am not sure if that just has to do with promoting electrons to higher energy orbitals.
 

Similar threads

Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K