Distance calculated from Energy

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Homework Help Overview

The discussion revolves around a physics problem related to the relationship between work, kinetic energy, and distance traveled by a particle. Participants are exploring how work done on the particle affects its kinetic energy and how this relates to the distance it travels.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial kinetic energy of the particle and its implications for the work-energy principle. There are questions about how work relates to distance and the role of initial velocity in calculating kinetic energy. Some participants attempt to clarify the relationship between force, work, and distance.

Discussion Status

The discussion is active, with participants providing insights and corrections regarding the initial conditions of the problem. Some guidance has been offered on how to approach the calculation of distance based on the kinetic energy and work done. Multiple interpretations of the problem are being explored, particularly concerning the initial kinetic energy and the effects of force.

Contextual Notes

There is a mention of specific values for kinetic energy and force, as well as a reference to a graph that may be relevant for understanding the work done on the particle. Participants are also navigating the constraints of the problem as posed in the homework context.

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Please help me with part b, thank you!
 
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Complete the following so the sentences are true:

The particle starts with ________J kinetic energy.
Work done on the particle increases/decreases it's kinetic energy.

Now how is the Work related to the distance the particle travels?

To help you properly, really need to see your working.
 
The particle starts with 0 J kinetic energy.

Force relates the work to the distance the particle travels.
 
The particle starts with 0 J kinetic energy.
Doesn't the particle have some initial velocity?

Select "increases" or "decreases" for the second sentence.
 
Well, at x=0, the Force is 2 Newtons but the x is 0, so wouldn't 2N * 0m = 0 J?

Work done on the particle increases it's kinetic energy.
 
OK - you've forgotten about the initial velocity. When I read part (b) I see this:

(b) if it starts with a velocity of 2m/s in the +x direction, how far will the particle go in that direction before stopping?

Thus - how much kinetic energy is it starting with?
 
Ooh okay, it's 1 J.
 
No worries - the eye sometimes skips part of a question. Hate it when that happens :)
 
Thanks :] So once I have 1 J, how do I solve for the distance? I added 1 J to the 3 J at x = 4. W = fd so.. 4 J = F d. What would be my F?
 
  • #10
You don't need F. Look at your graph. You did it correctly when you thought you started with 0J energy - do the same thing only starting with 1J

So - you start with 1J
In the first meter moved, you gain 1J (area under F-x graph) for a total of 2J
What happens in the next meter moved?
How far before you've lost all the KE?
 
  • #11
2.5m! Thanks so much, I really appreciate your help :)
 

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