- #1

slag1928

- 13

- 0

I've tried finding the area under the lines but that doesn't seem to be it...

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- Thread starter slag1928
- Start date

- #1

slag1928

- 13

- 0

I've tried finding the area under the lines but that doesn't seem to be it...

- #2

iamsolost22

- 5

- 0

I've tried finding the area under the lines but that doesn't seem to be it...

Velocity=distance/ time. multiply by the time stamp at whatever point you are on on the graph.

- #3

Aggression200

- 50

- 0

Using that, you should be able to figure out the position. (At least, that's how I do it.)

- #4

VACA

- 16

- 0

What did you do when you tried finding the area under the graph?

- #5

slag1928

- 13

- 0

completing each time increment as a triangle and using 1/2b*h.

- #6

VACA

- 16

- 0

completing each time increment as a triangle and using 1/2b*h.

Could you post a picture of the graph?

- #7

slag1928

- 13

- 0

maybe, let me try

- #8

slag1928

- 13

- 0

well uh no actually. idk how D: could i get an e-mail? i think i could e-mail it

- #9

slag1928

- 13

- 0

- #10

slag1928

- 13

- 0

it's #7 i need help with!

- #11

VACA

- 16

- 0

The blue graph right?

What ares did you use 1/2b * h on (what time)?

What ares did you use 1/2b * h on (what time)?

Last edited:

- #12

slag1928

- 13

- 0

- #13

VACA

- 16

- 0

What did you find for displacement?

- #14

slag1928

- 13

- 0

i got -54

- #15

VACA

- 16

- 0

Okay, and for what parts did you use 1/2b*h?

- #16

slag1928

- 13

- 0

time interval 3-4 seconds have a constant velocity of -18 m/s so i added -18 to the first -18 getting -36. then i found the are from 4-5 by multiplying 1/2 the base of 1 second, by the height of -9, getting an additonal -4.5. Sum of all these? -54!

- #17

slag1928

- 13

- 0

i meant times the height! sorry I'm a confusing typer !

- #18

slag1928

- 13

- 0

please ignore the first time i said "this got -36" its a typo...

- #19

VACA

- 16

- 0

time interval 3-4 seconds have a constant velocity of -18 m/s so i added -18 to the first -18 getting -36. then i found the are from 4-5 by multiplying 1/2 the base of 1 second, by the height of -9, getting an additonal -4.5. Sum of all these? -54!

You found the area for time 4-5s wrong.

You found the red part, but not the blue part. The blue part is a rectangle.

Also, I think for this problem you can assume displacement and distance are meant to be the same thing.

Last edited:

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