1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Distance the dog has to travel to catch a ball - projectile motion

  1. Apr 15, 2012 #1
    1. The problem statement, all variables and given/known data

    Jaime is outside playing with her dog, Skip. She throws a tennis ball at an angle of 60° with an initial speed of 10.2m/s and from a height of 196cm. If Skip was standing beside her when she threw the ball, how far would Skip have to run in order to catch the ball just the moment before it hits the ground?

    2. Relevant equations

    Kinetic equation d=Vi*t+ 1/2*at2
    dh=-V2*sin2θ /g
    Δt=-2Vsinθ / g

    3. The attempt at a solution

    dv= sin(60)*10.2m/s= 8.83m

    The actual vertical height for the dog is 1.96m+8.83m=10.8m


    Then dv=1/2*at2= 25.9m

    If someone could just verify my work and make sure my answers are correct that would be greatly appreciated. Also, if you could check my significant figures are being respected. Thanks so much in advance!
  2. jcsd
  3. Apr 15, 2012 #2
    Why do you get that height for the height of the dog? -where does the 8.83m come from?

    What I did is found the time using s=ut+1/2at^2, solved that, got two answers, one of them negative which isn't valid.
    Using this equation 10.2*t*sin60 -4.9t^2 +1.96=0, and solving gives the time as 2.0025 seconds. Then multiply this by the speed of the ball, negating air resistance, to get the horizontal distance. This gives you 2.0025*10.2cos60 = 10.21275m.
  4. Apr 17, 2012 #3
    Thank you so much for your time to look and address the issues i am having with this problem. I am just a little confused when it comes to the variables you used. What does the s represent? and same question goes for the u? If you clarify this with me that would be fantastic! thanks!
  5. Apr 17, 2012 #4
    Oh, s is the distance, u is the initial speed, v is the final speed a as acceleration and t as time.
  6. Apr 17, 2012 #5
    Thank you!
  7. Apr 17, 2012 #6
    This is a really stupid question but what do you by you got two answers and one of them was negative?
  8. Apr 22, 2012 #7
    I redid the question and got 10.21m as well! Thank you very much! :)
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook