Find initial velocity and time in the air- projectile motion

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SUMMARY

The discussion focuses on calculating the initial velocity and time in the air for a projectile motion problem involving a soccer ball kicked at an angle of 38.0°. The initial velocity was determined to be 3.14 m/s using the equation d = Vi*t + 1/2*at², while the time in the air was calculated to be 7.96 seconds. The calculations utilized key equations such as dh = Vh*Δt and Δt = -2Vsinθ / g. The participant sought confirmation on the accuracy of their answers and adherence to significant figures.

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dani123
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1. Homework Statement

A soccer ball is kicked at 38.0° with respect to the horizontal and travels 64.0m before striking the ground.
a) what is its initial velocity?
b) how long was it in the air?

2. Homework Equations

dv=1/2*at2
dh=Vh*Δt
Kinetic equation d=Vi*t+ 1/2*at2
dh=-V2*sin2θ /g
sinθ=opp/hyp
cosθ=adj/hyp
Δt=-2Vsinθ / g

3. The Attempt at a Solution

a) dh=cos(38)*64m= 50.4m
dv=sin(38)*64m=39.4m

Find t=√(39.4m/(0.5*9.8))=7.96s

plug this value into the d=Vi*t+ 1/2*at2 equation and solve for Vi if d=64m

Vi=3.14m/s

b) V=dh/Δt= 50.4m/7.96s=6.33m/s

Then solve for Δt=-2Vsinθ / g= 0.80s

I would like for someone to just double check my answers and that I used the appropriate equations and that the number of significant figures are being respected! Thanks so much in advance!
 
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Sorry, last answer is bad, it looks okay. I would consider the highest y it takes and use energy conservation(kinetic energy) to obtain the initial velocity
 
Last edited:

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