A soccer ball is kicked at 38.0° with respect to the horizontal and travels 64.0m before striking the ground.

a) what is its initial velocity?

b) how long was it in the air?

2. Relevant equations

dv=1/2*at2

dh=Vh*Δt

Kinetic equation d=Vi*t+ 1/2*at2

dh=-V2*sin2θ /g

sinθ=opp/hyp

cosθ=adj/hyp

Δt=-2Vsinθ / g

3. The attempt at a solution

a) dh=cos(38)*64m= 50.4m

dv=sin(38)*64m=39.4m

Find t=√(39.4m/(0.5*9.8))=7.96s

plug this value into the d=Vi*t+ 1/2*at2 equation and solve for Vi if d=64m

Vi=3.14m/s

b) V=dh/Δt= 50.4m/7.96s=6.33m/s

Then solve for Δt=-2Vsinθ / g= 0.80s

I would like for someone to just double check my answers and that I used the appropriate equations and that the number of significant figures are being respected! Thanks so much in advance!