Distance traveled by the object in n-th second

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The discussion centers on understanding the calculation of distance traveled during the nth second, which is derived by subtracting the distance covered in the first n-1 seconds from that of the first n seconds. This method highlights the specific distance an object travels in that particular second. There is skepticism about the necessity of this equation, especially considering its limitations with varying time units. The conversation reflects confusion over the relevance and application of this concept in physics. Overall, the distinction between the nth and (n-1) second is crucial for precise calculations in kinematics.
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Homework Statement
I dont understand what this mean lol
Relevant Equations
S = S_o + v_o + \frac{1}{2}at^2
Screenshot_1.png

Hi! I don't understand why is made the difference between the n second and the (n - 1) second. Can anyone help me? Thanks!
 
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niett said:
Homework Statement:: I don't understand what this mean lol
Relevant Equations:: S = S_o + v_o + \frac{1}{2}at^2

View attachment 281778
Hi! I don't understand why is made the difference between the n second and the (n - 1) second. Can anyone help me? Thanks!
The distance traveled in the nth second is the distance traveled in the first n seconds minus the distance traveled in the first n-1 seconds.
But why anyone would bother to develop such an equation (to be remembered?) is beyond me, especially since it breaks down if using different units for time.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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