That's what I'm having trouble determining; what do I use for "do" in my second calculation?mfb said:
if di1 = -20cm, doesn't that place it behind the concave lens?mfb said:
If I had to guess I'd say to the right of Lens 2mfb said:
Again, this is the piece I do not understand.DrewHizzy said:
I answered Part A correctly with 9.6cm, hi/ho = di/do for part B? Do I make two calculations like Part A?mfb said:
A diverging lens is thinner at the center and thicker at the edges, causing light rays to spread out or diverge. On the other hand, a converging lens is thicker at the center and thinner at the edges, causing light rays to come together or converge.
A diverging lens causes light rays to spread out or diverge, making objects appear smaller and more distant than they actually are. This type of lens is used in glasses for nearsightedness.
The focal length of a converging lens is the distance from the center of the lens to the point where parallel light rays converge. It is usually measured in meters or centimeters.
A converging lens bends light rays so that they converge at a specific point, forming a real or virtual image. The size and position of the image depend on the distance of the object from the lens and the focal length of the lens.
Diverging and converging lenses are used in combination to correct visual impairments and create magnifying or reducing systems. They are also used in cameras, telescopes, and other optical instruments to focus light and form images.