Diverging lens, calculating image location

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SUMMARY

The discussion focuses on calculating the image location for a diverging lens with a focal length of -2 meters and an object distance of 3.66 meters. The formula used is the lens formula: 1/object + 1/image = 1/f. The calculation yields an image distance of -1.29 meters, indicating that the image is virtual and located in front of the lens, consistent with the sign convention for thin lenses. The ray diagram corroborates this finding, confirming the accuracy of the calculations.

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Homework Statement



Diverging lens with focus of 2 meters. The object is 3.66 meters away from the lens. Find the exact image location.

Homework Equations



1/object + 1/image = 1/f

The Attempt at a Solution



I plugged in the numbers with a negative value for the focal length but I keep getting a negative value (-1.29 m) for my image location. However, when I do the ray diagram (which I'm confident is correct) I find that the image should be in front of the lens. Any explanations?
 
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The usual sign convention for thin lenses is such that the image distance is negative if the image is in front of the lens.
 

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