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## Main Question or Discussion Point

A friend posed this just for fun but now its really annoying me.

how do you divide 90 into three parts so that each part is 1.6 times greater than the last.

i.e: the second value should be 1.6 times greater than the first and the third value should be 1.6 times greater than the second?

Im confusing myself with this.

Thanks

how do you divide 90 into three parts so that each part is 1.6 times greater than the last.

i.e: the second value should be 1.6 times greater than the first and the third value should be 1.6 times greater than the second?

Im confusing myself with this.

Thanks