Dividing Exponential Functions

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Dividing two exponential functions can be approached by substituting e^x with a variable, such as y, to simplify the expression. For example, when dividing functions of the form A*e^(Cx) + B by O*e^(Px) + Q, the expression can be rewritten as (Ay + B)/(Oy + Q). This method allows for the identification of a remainder, which may not yield a straightforward simplification. Additionally, converting the functions into linear expressions using natural logarithms may be complicated due to logarithmic rules. The goal is to establish a relationship between the variables n and v, which requires further exploration and assistance.
impendingChaos
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How would one go about dividing two exponential functions.
Basically I have f(x)=k*g(x)
So to solve for k, k=f(x)/g(x)
How would one accomplish this when the functions are both within the format:
A*e^(Cx)+B

Thanks
 
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There's usually no nice simplification when there's a sum in the denominator.
 
There is a way to simplify, but it's not necessarily what you are looking for. You might or might not end up with an invariant remainder. Here:

\frac{Ae^{Cx} + B}{Oe^{Px} + Q}

For example, let's say A = 1 and P = 1\frac{Ae^{x} + B}{Oe^{x} + Q}

Make the substitution e^x = y and get

\frac{Ay + B}{Oy + Q}

Now we can write

\frac{A/O(Oy + Q - Q) + B}{Oy + Q}

\frac{A/O(Oy + Q ) - QA/O + B}{Oy + Q}

A/O + \frac{B - QA/O}{Oy + Q}

B - QA/O is the remainder here.
 
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Hmm I will try your method Werg but like you say I am not sure it is what I am looking for.
I am also trying to make both individual functions into linear expressions by taking the natural log of both sides however I run into natrual log rules which keep this from succeeding. Any ideas in the department?
Another note, I would like to clarify that I should have represented the functions as something like:
f(n)
g(v)
they are both describing different attributes of a system. What I am trying to accomplish is finding a relationship between n and v. Still working towards a solution so any help greatly appreciated.

C.N.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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