D'Lembert Method for Solving the Wave Equation with Boundary Conditions

  • Context: MHB 
  • Thread starter Thread starter Markov2
  • Start date Start date
  • Tags Tags
    Application Method
Click For Summary
SUMMARY

The discussion focuses on applying the D'Lembert Method to solve the wave equation given specific boundary and initial conditions. The equation under consideration is \( u_{tt} = u_{xx} \) for \( x > 0 \) and \( t > 0 \), with boundary condition \( u(0,t) = 0 \) and initial conditions \( u(x,0) = x e^{-x^2} \) and \( u_t(x,0) = 0 \). Participants clarify the handling of the boundary condition at \( (0,0) \) and confirm that it can be ignored if the solution satisfies the other conditions. The method is validated through practical application.

PREREQUISITES
  • Understanding of wave equations, specifically \( u_{tt} = u_{xx} \)
  • Familiarity with the D'Lembert Method for solving partial differential equations
  • Knowledge of boundary and initial value problems in mathematical physics
  • Basic calculus and differential equations concepts
NEXT STEPS
  • Study the D'Lembert Method in greater detail, focusing on its application to various boundary conditions
  • Explore the implications of different initial conditions on wave equation solutions
  • Learn about other methods for solving wave equations, such as separation of variables
  • Investigate numerical methods for approximating solutions to wave equations
USEFUL FOR

Mathematicians, physicists, and engineering students interested in solving wave equations and understanding boundary value problems in mathematical modeling.

Markov2
Messages
149
Reaction score
0
Solve

$\begin{aligned} & {{u}_{tt}}={{u}_{xx}},\text{ }x>0,\text{ }t>0 \\
& u(0,t)=0,\text{ }t>0 \\
& u(x,0)=x{{e}^{-{{x}^{2}}}},\text{ }0<x<\infty \\
& {{u}_{t}}(x,0)=0.
\end{aligned}
$

The condition $u(0,t)$ is new to me, since I usually apply the method when only having $u(x,0)$ and $u_t(x,0),$ what to do in this case?
 
Physics news on Phys.org
The boundary and intial value conditions match at (0, 0) so I would just ignore it, then check to make sure my result satisfied that.
 
Okay, I'll apply it then and see how it works, thanks!
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K