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Equation (2) contains the assumption of statistical independence, but it also contains more - the partition assumption. Ie. the assumption that it makes senses to partition the probability into an average over the outcome given by the hidden variable.PeterDonis said:I'm not sure what you mean. Equation (2) in that paper is the locality assumption: the result ##A## does not depend on the settings ##\vec{b}## and vice versa. Other assumptions, including anything you might want to relate to "causality", are elsewhere in the paper.
partition assumption
$$P(A,B |O_ {A}) = \sum_{\lambda} P(A,B|\lambda|O_ {A}) P(\lambda|O_ {A})$$
statistical independence
$$P(A,B |O_ {A}) = \sum_{\lambda} P(A|\lambda|O_ {A}) P(B|\lambda|O_ {A}) P(\lambda|O_ {A})$$
$$\sim \int_{\lambda} P(A|\lambda) P(B|\lambda) d \lambda$$
The partition assumption makes sense there the causal role of the hidden variable is of the simple "experimenter ignorance type", and compliant also to the old pool-table realism. But other causal mechanisms that still make use of hidden variables are still possible, I am thinking of those that can be thought of as subjective, but still real.
So all Bell theorem disproves is the "naive" ignorance type of HV mechanism.
/Fredrik