Do not get Logarithmic antiderivatives

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SUMMARY

The discussion centers on the antiderivative of the function $$\frac{1}{x}$$, which is $$ln \vert x \vert$$. The user examines the expression $$(x-a) ln (\vert x-a\vert)-x$$ and finds that its first derivative yields $$ln (\vert x-a \vert)$$. However, when substituting into the equivalent expression $$(x-a) ln (\vert a -x\vert)-x$$, the user encounters a discrepancy in results. The forum participants emphasize the necessity of providing detailed calculations to identify the source of the error.

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Students and professionals in mathematics, particularly those studying calculus and seeking to deepen their understanding of antiderivatives and logarithmic functions.

muzialis
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Dear All,

the antiderivative of $$\frac{1}{x}$$ is $$ln \vert x \vert $$.
If I then consider the expression $$ (x-a) ln (\vert x-a\vert)-x $$ and compute the first derivative I obtain $$ ln (\vert x-a \vert)$$.
If I then consider the equivalent expression $$ (x-a) ln (\vert a -x\vert)-x $$ I do not get the same result, where is my mistake??
 
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muzialis said:
If I then consider the equivalent expression $$ (x-a) ln (\vert a -x\vert)-x $$ I do not get the same result, where is my mistake??

We can't answer that unless you show us what answer you got. And your working.
 

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