Do these 3 systems of equations all all define the same curve?

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SUMMARY

The discussion confirms that all three systems of equations define the same curve, specifically a circle in the yz-plane where y² + z² = 1, intersecting at x = 0. The first system includes a sphere and a cylinder, while the second and third systems involve the yz-plane and a cylinder, respectively. The intersection points of these equations consistently yield the same circular curve.

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nickadams
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Homework Statement



Consider three systems of equations:

x^2 + y^2 + z^2 = 1
y^2 + z^2 = 1

x^2 + y^2 + z^2 = 1
x = 0

y^2 + z^2 = 1
x = 0

Which of these define the same curve and which define different ones?

Homework Equations



x^2 + y^2 + z^2 = R^2 is a sphere
x,y, or z = # is a plane
(x,y,z)^2 + (x,y,z)^2 = # is a cylinder

The Attempt at a Solution



I think they all define the same curve; here is why...

Equation 1 of the first system is a sphere centered at the origin with a radius of 1.
Equation 2 of the first system is a cylinder centered around the x axis.
The curve represented by those two equations is the points where both equations are satisfied; AKA: where they intersect. They intersect at x=0 in a circle given by y^2+z^2 = 1 .

Equation 1 of the second system is a sphere centered at the origin with a radius of 1.
Equation 2 of the second system is the yz plane at x=0.
The curve represented by those two equations is the points where both equations are satisfied; AKA: where they intersect. They intersect at x=0 in a circle given by y^2+z^2 = 1 .


Equation 1 of the third system is a cylinder centered at the x-axis with a radius of 1.
Equation 2 of the third system is the yz plane at x=0.
The curve represented by those two equations is the points where both equations are satisfied; AKA: where they intersect. They intersect at x=0 in a circle given by y^2+z^2 = 1 .




Am I right?:biggrin:
 
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