A Does 15F Qualify as an sd Shell Nucleus?

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The discussion centers on whether 15F can be classified as an sd shell nucleus based on the positions of its last proton and neutron. In 15F, the last proton occupies the 1d5/2 orbit, while the last neutron is in the 1p3/2 orbit. This raises the question of whether both nucleons need to be in the sd shell for the classification. The distinction between open and closed sd-shell nuclei is also highlighted as a relevant factor in determining the classification. Ultimately, the classification of 15F as an sd shell nucleus remains ambiguous based on these criteria.
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TL;DR
In nuclear shell model, the shell where the last proton or neutron lies is important. It relates to the property of the nuclei. But what is the definition of sd shell nuclei?
If we call a nucleus a sd shell nucleus, should its last proton and last neutron both lie in the sd shell or just one lies in the sd shell?
For example, 15F, whose proton number is 9 and neutron number is 6. Then the last proton lies in the 1d5/2 orbit and the last neutron lies in the 1p3/2 orbit. So can we call 15F the sd shell nucleus? Thanks a lot!
 
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There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
 
malawi_glenn said:
There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
I get your point. Thanks very much.
 
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