A Does 15F Qualify as an sd Shell Nucleus?

amyy
Messages
8
Reaction score
2
TL;DR Summary
In nuclear shell model, the shell where the last proton or neutron lies is important. It relates to the property of the nuclei. But what is the definition of sd shell nuclei?
If we call a nucleus a sd shell nucleus, should its last proton and last neutron both lie in the sd shell or just one lies in the sd shell?
For example, 15F, whose proton number is 9 and neutron number is 6. Then the last proton lies in the 1d5/2 orbit and the last neutron lies in the 1p3/2 orbit. So can we call 15F the sd shell nucleus? Thanks a lot!
 
Physics news on Phys.org
There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
 
malawi_glenn said:
There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
I get your point. Thanks very much.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...

Similar threads

Replies
4
Views
6K
Replies
4
Views
2K
Replies
3
Views
1K
Replies
15
Views
3K
Replies
3
Views
2K
Replies
2
Views
2K
Back
Top