Does a Black Hole Represent a State of Absolute Rest in the Universe?

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SUMMARY

The discussion centers on the concept of black holes and their relationship to absolute rest in the universe. Participants explore the implications of time stopping at the event horizon and whether the center of a black hole can be considered a state of absolute rest. It is established that while light cannot escape a black hole due to gravitational redshift, an observer falling into a black hole experiences normal metrics until reaching the singularity. The Schwarzschild radius is referenced as a critical point in understanding these phenomena.

PREREQUISITES
  • Understanding of black hole physics, specifically event horizons and singularities
  • Familiarity with the concept of gravitational redshift
  • Knowledge of the Schwarzschild radius and its calculation
  • Basic principles of general relativity and spacetime metrics
NEXT STEPS
  • Study the Schwarzschild radius and its implications in black hole physics
  • Learn about gravitational redshift and its effects on light near black holes
  • Explore the metrics of spacetime in general relativity, particularly in relation to black holes
  • Investigate the experiences of observers falling into black holes and the concept of proper time
USEFUL FOR

Astronomers, physicists, and students of astrophysics interested in the nature of black holes and the fundamental principles of general relativity.

Gorn
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Hello...

If time stops at the event horizon of a black hole..which means there is no motion happening or can be observed..does that not mean that the centre of a black hole is a place of absolute rest?

Could such a place of ab/rest 'move' thru the cosmos (basically a black hole which is a dead star) from its place of birth?

I would think that the centre of black holes would fill the role of the 'Either'...where both objects and light would have a relative speed with respect to a place of ab/rest?

Why can a light wave not leave the region of a black hole?

Thank you for any and all responses..it will help me to pin down certain ideas I have.
Bye
G
 
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Use the escape velocity formula with v=c to get the schwarzschild radius.
If you calculate the http://en.wikipedia.org/wiki/Gravitational_redshift" for light moving normally away, you get z→∞ as r→rs+, so for r=rs it is physically dead
 
Last edited by a moderator:
Gorn said:
Hello...

If time stops at the event horizon of a black hole

It is oversimplified popular explanation.
Yes, light from horizon gets infinitely redshifted.
But for the falling observer nothing happens when he crosses the event horizon.
For the free falling observer metrics is normal (locally) all the way to singularity
 

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