Does an Electric Field Exponentially Decrease in Free Space?

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SUMMARY

The discussion centers on the behavior of electric fields in free space, specifically whether an electric field can decrease exponentially. The potential function given is V = F(x,y,z)e^{-y^2}, which decays exponentially in the y-direction. The Laplacian operator applied to this potential leads to the equation \nabla^2V=0, indicating that the exponential term cannot persist in the electric field or potential. The separation of variables approach reveals that the general solution does not support the existence of an exponential decay in free space.

PREREQUISITES
  • Understanding of Laplacian operator in three dimensions
  • Familiarity with potential theory in electrostatics
  • Knowledge of separable variables in differential equations
  • Basic concepts of electric fields and potentials
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  • Study the implications of \nabla^2V=0 in electrostatics
  • Explore the method of separation of variables in partial differential equations
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This discussion is beneficial for physics students, electrical engineers, and researchers focused on electrostatics and field theory, particularly those analyzing potential functions and electric field behavior in free space.

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Homework Statement


Can an electric field drops exponentially? (in free space)

Homework Equations


Starting from a hypothetical potential, [tex]V = F(x,y,z)e^{-y^2}[/tex] which decays exponentially in the y direction
[tex]\nabla^2V=0[/tex]

The Attempt at a Solution


[tex]\nabla^2V=e^{-y^2}(\frac{\partial^2F}{\partial x^2}+\frac{\partial^2F}{\partial z^2}+\frac{\partial^2F}{\partial y^2}-4y\frac{\partial F}{\partial y}+(4y^2-2)F)=0[/tex]
Using separable variable, the general solution of [tex]\frac{\partial^2F}{\partial y^2}-4y\frac{\partial F}{\partial y}+(4y^2-2)F=0[/tex] has the form [tex](A+By)e^{y^2}[/tex], assuming that all general solutions of the above equation can be expressed as a linear combination of the product of the 3 individual solution of the separable variable, we can see that the exponential term will cancel out.

I am not sure how to proceed from here, is this correct? does it mean we cannot have the exponential term in either potential or e field?
 
Last edited:
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You forgot the separation constant, i.e.

[tex]\frac{\partial^2F}{\partial y^2}-4y\frac{\partial F}{\partial y}+(4y^2-2)F=k^2[/tex]
 

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