Does C^n – B^n = A^n express A in terms of B and C?

[chuck klasky]

I have been studying the Pythagorean theorem and Fermat’s Last theorem for fun and to brush up on my algebra.
I think I’ve come up with an equation for redefining An in terms of B and C. But my math is too rusty to verify if its correct.
I hope you look at it and see if there is a mistake somewhere. Thanks

C^n – B^n = A^n
C – B = Q so C/Q – B/Q = Q/Q =1.
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[C^n-B^n]/Q^n = C^n/Q^n – B^n/Q^n = (C/Q)^n- (B/Q)^n = (C/Q)^n – ((C-Q)/Q)^n
= (C/Q)^n – (C/Q – Q/Q)^n = (C/Q)^n – (C/Q -1)^n { C-B = Q }
= (C / C-B)^n – ( (C/ C-B) – 1)^n and so
[Cn-Bn]/(C-B)^n = (C / C-B)^n – ( (C/ C-B) – 1)^n and therefore
Cn-B^n = (C-B)^n [(C / C-B)^n – ( (C/ C-B) – 1)^n] = A^n

 

[MarkFL]

Hello Chuck!

I would highly recommend learning to typeset your work using $\LaTeX$...this makes the reading of math expressions much easier on the reader. We have tools present to aid users in the construction and previewing of their code as well. :D

 

[chuck klasky]

Sure-thanks. How? Where is the lesson plan?
chuck

 

[Jameson]

Sure-thanks. How? Where is the lesson plan?
chuck

Hi Chuck,

If you take a look at our http://mathhelpboards.com/latex-help-discussion-26/ then you can find some basic info but for this problem I'll try to give you some specific hints. :)

You can put equations between $$...$$ tags, or click the sigma sign you see in the toolbar when you are writing something.

For exponents, all you have to do is write them as you are already doing.

a^b becomes $$a^b$$

For fractions you make them like this:

\frac{a}{b} becomes $$\frac{a}{b}$$

Does that give you a start?