Does -e^(-infinity) Equal 0 in Mathematics?

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SUMMARY

The expression -e^(-infinity) equals 0, as established by the limit of e^x as x approaches negative infinity. Specifically, the limit \lim_{x\rightarrow\infty} -e^{-x} confirms that -e^{-x} approaches -0, which is mathematically equivalent to 0. This conclusion is supported by the properties of exponential functions in calculus.

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does -e^(-infinity) equals 0?
 
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The limit of e^x as x-->-infinity is 0.
 
Are you referring to \lim_{x\rightarrow\infty} -e^{-x} ?
 
yes...
 
As kamataat said, \lim_{x\rightarrow\infty} e^{-x}= 0 and so
\lim_{x\rightarrow\infty} -e^{-x}= -0= 0.
 
i see. thanks.
 

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