1. The problem statement, all variables and given/known data You exert a force of 131 N [30° below horizontal] onto a 12.6 kg lawn mower, What is the force of gravity and normal force on the lawn mower? 2. Relevant equations Fg= m × g FA (y component) = Sin30° × FA 3. The attempt at a solution The force of gravity is equal to the force of normal, ∴ FN = m × g = 12.6 kg × 9.8 m/s2= 123.48 [up] But, the normal force gets added on by the force opposing the y component of the applied force right? So, FA (y component)Sin30° × FA = 65.5 N [down]So by newtons 3rd law there would be a force acting up on the lawn mower of 65.5 N[up]. I'm just wondering if these two forces are added to each other for the total normal force which is 123.48 N + 65.5 N = 188.98 N [up]?