(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

You exert a force of 131 N [30° below horizontal] onto a 12.6 kg lawn mower, What is the force of gravity and normal force on the lawn mower?

2. Relevant equations

F_{g}= m × g

F_{A (y component)}= Sin30° × F_{A}

3. The attempt at a solution

The force of gravity is equal to the force of normal,

∴ F_{N}= m × g

= 12.6 kg × 9.8 m/s^{2}= 123.48 [up]

But, the normal force gets added on by the force opposing the y component of the applied force right?

So, F_{A (y component)}Sin30° × F_{A}

= 65.5 N [down]So by newtons 3rd law there would be a force acting up on the lawn mower of 65.5 N[up].

I'm just wondering if these two forces are added to each other for the total normal force which is 123.48 N + 65.5 N = 188.98 N [up]?

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# Homework Help: Does force normal change when you push an object at an angle?

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