Does Gravity always move an object down the path with the steepest slope?

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SUMMARY

The discussion centers on the relationship between gravity and the steepest slope an object can take when moving along a surface. The user explores the concept of vector gradients in calculus and formulates a question regarding the work required to move an object from the bottom to the top of a hemisphere at a constant angle of elevation θ. The assumption made is that the resultant force of gravity always directs down the steepest slope, which aligns with the understanding of forces acting on an object at rest on a flat surface. The conversation emphasizes the importance of considering the normal force in this context.

PREREQUISITES
  • Understanding of vector gradients in calculus
  • Knowledge of gravitational force and its effects on objects
  • Familiarity with the concept of normal force
  • Basic principles of physics related to motion on surfaces
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  • Research the mathematical formulation of work done against gravity
  • Explore the implications of friction on motion along a slope
  • Study the relationship between normal force and gravitational force
  • Learn about the applications of vector calculus in physics
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Students of physics, mathematicians interested in calculus applications, and anyone exploring the dynamics of forces on inclined surfaces.

PeteyCoco
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Does gravity always move an object down the path with the steepest slope?

I just finished reading about the vector gradient in calculus and a problem jumped in my head:

"Can I make a formula for the work it takes to push an object from the bottom of a hemisphere to the top along the surface with a constant angle of elevation θ to the xy-plane?"*

I think I worked it out, but I made the assumption the resultant force of gravity always points down the steepest part of the surface. This makes sense to me instinctively since an object is at rest when it's on a flat surface (max slope = 0), but I wanted to know if there was a better way to state this.

I'm having so much fun with these things :-p

*Friction is a variable so no W=mgh
 
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If I've understood the question, you are asking..

Does the resultant of gravity and the normal force allways act down the steepest part of the slope.

Perhaps think about the definition of the normal force.
 

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