Does mass affect the amount of work done?

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SUMMARY

The amount of work done does not depend on the mass of the object when the applied force and displacement remain constant. According to the work formula W=F*s, where F is the force and s is the displacement, the work done is calculated as the product of force and distance. In scenarios where a 4 kg block and a 20 kg block are moved over the same distance with the same force of 6 Newtons, the work done remains 18 Joules. Therefore, increasing mass does not increase work when force and distance are unchanged.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy principle
  • Knowledge of basic physics formulas, specifically W=F*s and F=m*a
  • Ability to perform unit conversions and calculations in physics
NEXT STEPS
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  • Learn about the implications of varying forces and displacements on work done
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n124122
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Homework Statement


Is the amount of work depending on the mass?

Homework Equations


W=F*s
F=m*a

The Attempt at a Solution


attempt one:
because if you have a higher mass, it takes longer to make a certain object move over a certain distance, but it doesn't matter because time isn't measured. For example move a 4kg block over 3 meters with 6 Newton or move a 20 kg block over 3 meters with 6 Newtons, the work remains the same (3*6=18J).
Attempt two:
But when the mass is increased, in the formula F=m*a, the force is increased. So the work in the situation above should be increased? thereby making the work (20/4=5) 5 times bigger. What am i doing wrong?
 
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n124122 said:
attempt one:
because if you have a higher mass, it takes longer to make a certain object move over a certain distance, but it doesn't matter because time isn't measured. For example move a 4kg block over 3 meters with 6 Newton or move a 20 kg block over 3 meters with 6 Newtons, the work remains the same (3*6=18J).
Good. As long as the force and the displacement are the same, the work done will be the same.

n124122 said:
Attempt two:
But when the mass is increased, in the formula F=m*a, the force is increased. So the work in the situation above should be increased? thereby making the work (20/4=5) 5 times bigger. What am i doing wrong?
In the above, the applied force is kept the same. So when the mass is increased, the acceleration is decreased. But so what?
 
Doc Al said:
Good. As long as the force and the displacement are the same, the work done will be the same.In the above, the applied force is kept the same. So when the mass is increased, the acceleration is decreased. But so what?

thank you very much
 

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