Does Normal Force Do Work in Vertical Motion?

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SUMMARY

The discussion centers on the work done by various forces acting on a 2 kg object being pulled upward with an acceleration of 2.2 m/s². The participant calculated the displacement as 9.9 m, with the applied force contributing 43.56 J, the normal force (Fn) contributing 150.678 J, and gravitational force (Fg) contributing 194.238 J. The total mechanical work was calculated as -0.678 J, and the net force was determined to be 4.4 N upward, with the work done by the net force also being 43.56 J. The participant expressed confusion regarding the inclusion of Fn and Fg in vertical motion scenarios.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with work-energy principles
  • Knowledge of force calculations in vertical motion
  • Basic grasp of kinematics equations
NEXT STEPS
  • Study the concept of work done by normal force in vertical motion scenarios
  • Learn how to calculate net work using the work-energy theorem
  • Explore the implications of gravitational force on objects in vertical motion
  • Review kinematic equations for objects under constant acceleration
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces and work in vertical motion scenarios.

Vontox7
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Hello,
I have become very confused after i tried to solve this question.
A rope pulls a 2 kg object straight up, accelerating it from rest at 2.2 m/s^2 for 3 seconds.
they want the work done by each force acting on it.
Ok i found the displacement as 9.9 m up. Then i found out that the applied force does 43.56 J and that Fn does 150.678 J and gravity does 194.238 J .

Then they ask for the total mechanical work done. I just added the works and got -.678 . Then they ask for the net force which is 4.4 N up and work done by the net force which is 43.56 J.

I am confused about finding the net work when fg,fn, fapp are involved what am doing wrong. Also when solving other questions do i include fn and fg when the displacement is vertical?

Please help and thank you. i would add more detail but i got no time to study.
 
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E initial = E final

0 = - mg*X + F*X + mV^2/2

You can figure out all three.

?
 
I am sorry but i don't understand your formula. yes, i know that initial potential and kinetic energy equal the final but the next line i don't understand what it is nor how it can help.
 
Vontox7 said:
Hello,
I have become very confused after i tried to solve this question.
A rope pulls a 2 kg object straight up, accelerating it from rest at 2.2 m/s^2 for 3 seconds.
they want the work done by each force acting on it.
Ok i found the displacement as 9.9 m up. Then i found out that the applied force does 43.56 J and that Fn does 150.678 J and gravity does 194.238 J .

Then they ask for the total mechanical work done. I just added the works and got -.678 . Then they ask for the net force which is 4.4 N up and work done by the net force which is 43.56 J.

I am confused about finding the net work when fg,fn, fapp are involved what am doing wrong. Also when solving other questions do i include fn and fg when the displacement is vertical?

Please help and thank you. i would add more detail but i got no time to study.
What is Fn, a normal force? Are you sure there is a normal force acting on the object while it is accelerating upward?
 

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