Does scalar multiplication affect the cross product of vectors?

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SUMMARY

The discussion focuses on the properties of the cross product of vectors under scalar multiplication, specifically proving that k(a × b) = (ka) × b = a × (kb). The correct definition of the vector cross product is emphasized, clarifying that |A × B| equals |A| * |B| * sin(angleAB), but A × B itself is a vector, not a scalar. Participants are encouraged to demonstrate their calculations directly in the forum for clarity and to avoid using external documents.

PREREQUISITES
  • Understanding of vector operations, specifically vector cross product
  • Familiarity with scalar multiplication in vector spaces
  • Knowledge of vector notation and components (e.g., )
  • Basic principles of precalculus, particularly trigonometry related to vectors
NEXT STEPS
  • Research the properties of vector cross products in 3D space
  • Learn how to calculate cross products using determinants
  • Explore the geometric interpretation of the cross product
  • Study the implications of scalar multiplication on vector magnitudes and directions
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Students studying precalculus, educators teaching vector mathematics, and anyone interested in understanding vector operations and their properties in physics and engineering contexts.

amy098yay
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Mod note: Member warned about posting with no effort.

1. Homework Statement

Expand to the general case to explore how the cross product behaves under scalar multiplication k (a x b) = (ka) x b = a x (kb).

The Attempt at a Solution


would this be the right general case to portray the situation?
 

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Can't you use the definition of vector cross product?

ie A x B = | A | * | B | * sin ( angleAB ) u

Where u is the unit vector perpendicular to both A and B such that A, B, and u form a right handed system.

EDIT amended the definition where I left out the unit vector part.
 
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You need to show an attempt. Normally I would issue a warning and possibly infraction points. You were hit with several points a day or so ago, and your posts have improved considerably, so I'll treat this one more informally.

The problem as you state it seems to be to prove that k (a x b) = (ka) x b = a x (kb). What you posted in the Word document is not any kind of attempt -- it seems to be just the statement of some larger problem

Please put your work directly in the input pane here - not in a PDF or Word file or other attachment. It's frustrating to have to open another window to view the work. Having the work right here makes it easier for us to insert a comment right where there is a problem.

One other thing. All of these vector problems fall under precalculus, not calculus, so I am moving this thread to that section (and leaving a forward link).
 
alright thanks
 
jedishrfu said:
Can't you use the definition of vector cross product?

ie A x B = | A | * | B | * sin ( angleAB )

That isn't the definition of the cross product. It is also incorrect. It is ##|A\times B|## that equals the right side but it still isn't the definition because ##A\times B## is a vector, not a scalar.
 
amy098yay said:
alright thanks
To do this (i.e., prove that k (a x b) = (ka) x b = a x (kb) ), let a, b, and c be arbitrary vectors such as a = <a1, a2, a3>, b = <b1, b2, b3>, and similar for c, and let k be an arbitrary scalar. Do not use specific numbers. Calculate all three cross products and show that they are all equal.
 
Sorry folks I left the unit vector part out in my haste to answer the question.
 

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