Does the Antiparticle of Meson K^0 Consist of \bar{d}s?

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SUMMARY

The discussion confirms that the antiparticle of the meson K^0, which consists of d\bar{s}, is indeed \bar{K}^{0}, composed of \bar{d}s. This conclusion is reached by applying the fundamental principle of particle-antiparticle relationships, where quarks are swapped with their corresponding antiparticles. The participants agree on this straightforward approach to understanding meson composition.

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Homework Statement


I have a question.
If meson [tex]K^{0}[/tex] consists of [tex]d\bar{s}[/tex] then its antiparticle [tex]\bar{K}^{0}[/tex] consists of [tex]\bar{d}s[/tex] ?



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The Attempt at a Solution



 
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Yup, just swap quarks with their antiparticles and vice versa.
 
Thank you!:)
 

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