Does the series converge or diverge?

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Homework Help Overview

The discussion revolves around determining the convergence or divergence of the series \(\sum^{∞}_{n=0} \frac{\cos(n \pi)}{5^n}\), which involves concepts from series analysis in calculus.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the nth term test and the ratio test, with some suggesting evaluating the cosine term for specific values of \(n\). There is also mention of absolute convergence and bounding the series.

Discussion Status

The discussion includes various approaches to analyze the series, with participants providing hints and suggestions for further exploration. There is no explicit consensus on the method to be used, but several productive lines of reasoning are being explored.

Contextual Notes

Participants are considering the implications of the cosine function and its behavior in the context of series convergence, while also addressing the potential for absolute convergence.

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Homework Statement


Determine if series converges or diverges.

Homework Equations


[itex]\displaystyle \sum^{∞}_{n=0} \frac{cos n* \pi}{5^n}[/itex]

The Attempt at a Solution


I have tried using the nth term test but not sure how to take the limit of cosine.
 
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whatlifeforme said:

Homework Statement


Determine if series converges or diverges.

Homework Equations


[itex]\displaystyle \sum^{∞}_{n=0} \frac{cos n* \pi}{5^n}[/itex]

The Attempt at a Solution


I have tried using the nth term test but not sure how to take the limit of cosine.

Why don't you try working out the value of that cosine term for the first few values of n and see what you get?

Another hint: absolute convergence.
 
First, [itex]cos(n\pi)[/itex] is just [itex](-1)^n[/itex] so this is [itex]\frac{(-1)^n}{5^n}[/itex] and the ratio test works nicely.
 
HallsofIvy said:
First, [itex]cos(n\pi)[/itex] is just [itex](-1)^n[/itex] so this is [itex]\frac{(-1)^n}{5^n}[/itex] and the ratio test works nicely.

What is ##\sum |a_n|##, can it be bounded in some way?

Then perhaps another test will clean the rest up for you.
 

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